Electrostatics and electromagnetism Flashcards

1
Q

How can the total amount of charge (Q) of matter be calculated?

A

Q = ne

n: number of particles
e: charge of each particle (eg. 1.6x10^-19 coulombs for one proton or -1.6x10^-19 coulombs for one electron)

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2
Q

What does the conservation of charge state?

A

That a net charge cannot be created but that charge can be transferred from one object to another. One way of charging substances is by rubbing them.

For example, glass rubbed on fur becomes positive and rubber rubbed on fur becomes negative. OBjects can also be charged by induction, which occurs when one charged object is brought near to another uncharged object, causing a charge redistribution in the latter to give ner charge regions. COnductors transmit charge readily. Insulators resist the flow of charge.

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3
Q

What is an electric field?

A

A field is generated by a charged object and it is that region of space around the object that will exert a force on a second object brought into that field. The field exists independently of that second object and is not altered by its presence. The force exerted on the second object depends upon that object and the field.

Charges exert forces upon each other through fields. The direction of a field is the direction a positive charge would move if placed in it. Electric field lines are imaginary lines which are in the same direction as E at that point. The direction is away from positive charges and towards negative charges (ie. the electric field is directed towards the decreasing potentials)

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4
Q

What is the absolute potential (V)?

A

A scalar that is defined at each distance (r) from a charge (Q) generating an electric field. It represents the negative of the work per unit charge in bringing a +q from infinity to r

V = Ep/q = kQ/r

Where 1 volts = 1 joule/coulomb

V = Ed for a parallel plate capacitor, where d: distance between the plates

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5
Q

What are equipotential lines? When is work done and when is it not done?

A

Lines (and surfaces) of equal V (absolute potential) and are perpendicular to electric field lines.

Work can only be done when moving between surfaces of equal V and is, therefore, independent of the path taken.

Work is not done when a charge (q) is moved along an equal potential (equipotential) surface (or line), because the component of force is zero along it.

Potential (V) is defined in terms of positive charges such that V is positive when a +Q and negative when a -Q. Potential (V) is added algebraically at a point (because it is scalar)

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6
Q

How do dipoles align in an electric field?

A

A force is exerted on the positive side (in the direction of the electric field) and a force is exerted on the negative end (in the direction away from the direction of the electric field)

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7
Q

What is an electric dipole?

A

An electric dipole consists of two charges separated by some finite distance (d). Usually the charges are equal and opposite. The laws of forces, fields, etc. .. apply to dipoles. A dipole is characterized by its dipole moment, which is the product of the charge (q) and d (distance).

dipole moment = (charge)(distance) = qd

Dipoles tend to line up with the electric field they’re in. Motion of dipoles against an electric field requires energy.

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8
Q

What does Coulombs law state about electrostatics?

A

It describes the nature of the forces acting upon electric charges at rest, and how new forces appear when the charges are moving. They are not of the same nature as the electrostatic forces, and they act differently on the electric charges. They are called:

Electromagnetic forces

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9
Q

What is the unit for the magnetic induction vector (B)?

A

The tesla

1 T = 1 N/(Axm) = 10^4 gauss

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10
Q

What is Laplace’s Law for the force acting upon a particle in a magnetic induction field (B)?

A

A a particle with charge dq moving at a velocity (v) in a magnetic induction field (B) is acted upon by a force dF, given by the following formula

dF = dq(v) x B = dq(v)(Bsinα)

α: angle formed by the direction of v with that of B (cross product)

The force dF is perpendicular to the magnetic induction vector and also to the displacement velocity of the charge

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11
Q

When many charges are in motion, they produce an electric current of intensity I (dq/dt).

How is the intensity calculated?

A

dq/dt

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12
Q

How can you determine the cross product (direction) of the velocity of a charged particle and an electromagnetic field?

A

The right-hand rule.

Fingers describe the circular motion around a wire, or the direction of the magnetic induction vector (B). The thumb point in the direction of current flow (flow of charged particles)

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13
Q

Which two perpendicular vectors exist at each point of an electromagnetic field?

A
  • The electric field vector (E)

- The magnetic induction field vector (B)

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14
Q

Give Planck’s equation for the relation between energy (E) and the frequency (f) of electromagnetic radiation

A

E = hf

Where h: Planck’s constant

Thus high frequency or short wave length corresponds to high energy and vice versa

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15
Q

In a vacuuum photodiode the photoelectric effect causes electrons to be ejected from a metal plate when photons of light are absorbed by the metal. The ejected electron will have a kinetic energy equal to the photon’s energy minus the work function (2x10^-19 J).

If an electron is ejected from a cathode by a photon with an energy slightly greater than the work function of the cathode, how will the final kinetic energy of the electron upon reaching the anode compare to its initial potential energy immediately after it has been ejected? Why?

Potential energy immediately after ejection is -1.6x10^-19 C

A

Final kinetic energy will be approximately equal to when the electron was ejected.

The near equality of the photon energy and work function means that little initial kinetic energy will be left for the electron. This initial kinetic energy is small compared to the 50 eV it will gain from the potential difference between electrodes.

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16
Q

To precess μ (an intrinsic property of subatomic particles) at a frequency of ωd, μ must be parallel to a magnetic field ( eg. B1).

If at resonance a magnetic field (eg. B2) rotates an H nucleus. What is the angle of rotation?

A

180 degrees.

If the precessing H atom becomes antiparallel, this means μ has turned by 180 degrees.

17
Q

True or false? The total charge of a piece of the interior of a conductor is zero. Any excess charge lies on the surface of the conductor.

A

True

18
Q

When a particle is moved closer or further away from a charge there is a delay in ‘response’ to the change. What causes this delay?

A

A disturbance in the electric field propagates outward at a finite speed - the speed of light.

That’s what light is: a disturbance in the electric field which propagates away from the source. Which is an accelerating charge

19
Q

A stationary charge (Q) creates at every point an electric field (E) of magnitude: (give formula)

What is the direction of the field?

A

E = kQ/d^2

-Q: Toward Q
+Q: Away from Q

20
Q

A charge placed at point P will experience a force given by: __ (formula)

A

F = qE

21
Q

What is the formula for calculating the work required to bring a charge from infinity to a point in an electric field (P)?

A

W = qV

Units are J/C = volts = V

V = electric potential at the point (P)

22
Q

How can you calculate the electric potential (V) at a certain point in an electric field?

A

V = k(Q/d)

23
Q

How can you calculate the force on an object due to a magnetic field?

A

The force is always perpendicular to the displacement of the particle, for this reason, magnetic forces do no work.

Any question that asks “how much work does the magnetic force..?” The answer is zero.

24
Q

What two things happen when capacitor plates are brought closer together but voltage is kept constant?

A
  • The electric field is increased
  • The capacitance is increased

A reduction in distance would reduce voltage potential across the plates and therefore increase capacitance.

E = V/d

25
Q

What is the equation for capacitance that you are going to write on your scrap piece of paper before the exam?

A

C = q/V = permittivity x A/d = Farad

26
Q

Give another formula for the force due to an electric field that utilizes a total number of excess charges.

A

Fe = n e E

n: total number of excess charges
e: The fundamental unit of charge (in coulombs)
E: the electric field

27
Q

A negatively charged droplet is dropped through a hole in a capacitor. It falls through when the electric field is 0 V/m. How does the drop move within the plates as the electric field is increased slowly from 0 V/m to 800 V/m?

Mass of drop: 5x10^-16 kg
Charge of drop: 8x10^-18 C

A
  1. Find E acting initially on the drop:

E = mg/q = ((5x10^-16 kg)(10 m/s^2))/8x10^-18 C = 625 V/m

The initial E is 625 V/m, acting downwards. The electric field of the capacitor is increased from 0 to 800 V/m. So the drop will fall, stop and then accelerate upwards.

28
Q

Define a semiconductor. How could heat be expected to increase the conductivity of a semiconductor?

A

A semiconductor is a solid substance that has a conductivity between that of an insulator and that of most metals, either due to the addition of an impurity or because of temperature effects. Devices made of semiconductors, notably silicon, are essential components of most electronic circuits.

Heat can increase the conductivity of a semiconductor by breaking covalent bonds and raising electrons to a higher energy level.

Breaking covalent bonds will allow the normally sp^3 hybridized silicon to move electrons from a filled valence band to the conduction band. Jumping to the higher energy band gap requires energy, which heat provides.

29
Q

A certain metal plate is completely illuminated by a monochromatic light source. Which of the following would increase the number of electrons ejected from the surface of the metal?

A. Increase the intensity of the light source
B. Increasing the frequency of the light source
C. Increasing the surface are of the metal plate

A

A. Increasing the intensity of the light source
C. Increasing the surface area of the metal plate

Increasing intensity increases number of photons hitting metal plate per second (E = hf). A is right.

E = hf tells us that the energy of the incident photons would increase with increasing light frequency, consequently ejecting electrons with a higher kinetic energy, however not increasing number of electrons ejected (same number of incident photons). B is wrong.

Increasing surface area will allow more photons to hit the plate and therefore more electrons will be ejected. C is right.

30
Q

Recall the weird mnemonic you use to remember the electromagnetic spectrum from radio to gamma waves.

A

Real Men Initiate Very Unusual seX Games

Radio - Microwave - Infrared - Visible - UV - X-ray - Gamma

31
Q

An electron of mass m and charge q in a solar flare bends in a circle while in Earth’s magnetic field B. What is the expression for the radius of the circle if the electron has a velocity v perpendicular to B?

A

(mv)/(qB)

The force on a charge moving in a magnetic field is perpendicular to both the velocity and the magnetic field. Therefore no work is done on the charge and the motion is circular. Magnetic force is:

F = qvB and the centripetal force on an object in uniform circular motion is:

F = mv^2/r

therefore r = mv/qB

32
Q

A magnetic force has a vectorial direction that is perpendicular or parallel to:

  • Velocity of a charged object
  • Direction of the magnetic field (B)
A

A magnetic force acts on a moving charged object that is perpendicular to BOTH the velocity of the charged object AND the direction of the magnetic field!

This is a basic law of the interaction of electric currents and magnetic fields.