Biology 1: Molecular Biology & Genetics Flashcards Preview

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Flashcards in Biology 1: Molecular Biology & Genetics Deck (85)
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1
Q

List the purines

A

G and A

2
Q

List the pyrimidines

A

C, U, T

3
Q

what are 2 components of intergenic regions?

A

transposons

tandem repeats

4
Q

T/F: a gene technically only encodes for a protein or RNA transcript but not the regulatory regions such as promoters and stop sites

A

FALSE it encodes for both

5
Q

esstrogen (estradiol) and testosterone are both examples of what type of hormone

A

steroid

6
Q

The most effective technique for sterilizing used laboratory materials is?

A

using an autoclave and should be the standard procedure followed here. An autoclave brings the materials to a temperature over 120ºC and a pressure over 2 atm, which is enough to kill almost anything.

7
Q

T/F: Both single- and double-crossover events will only affect one arm of each chromosome.

A

True

8
Q

T/F: Fungi are eukaryotes

A

true

9
Q

Copy number variation refers to

A

is when the number of copies of a particular gene varies from one individual to the next due to structural changes

10
Q

SNP’s are

A

small nucleotide polymorphisms

they differ from CNV in that they are only changes at the single nucleotide level, whereas CNV refers to larger ~103 bp long genes

11
Q

stop codons are also called ____ codons because ?

A

nonsense, because they don’t code for an amino acid

12
Q

the protein that is responsible for unwinding the DNA double helix so that replication can occur is called ______

does it require ATP?

A

helicase

yes it requires ATP hydrolysis

13
Q

What is the role of topoisomerase in unwinding DNA double helix?

A

prevents the upstream and downtream coils from getting too tightly wound

14
Q

Ligase is used for:

A

joining nascent DNA strand fragments (okazaki fragments and the fragment that replaced the primer)

15
Q

adding nucleotides requires which type of reaction

A

hydrolysis of pyrophosphate from each dNTP added to the chain

16
Q

Function of DNA Pol III vs DNA Pol I

A

DNA Pol III:

  1. super fast nucleotide addition,
  2. takes over from DNA pol I after baout 400 base pairs have been added.
  3. has 5’-3’ exonuclease activity via proofreading function

DNA Pol I:

  1. slower nucleotide addition
  2. starts adding from primer and is replaced after it has adde about 400 bps
  3. also has 5’-3’ exonuclease activity via proofreading function
  4. responsible for removing primer and replacing it with DNA
  5. also has a role in excision repair

exonuclease: cutting from the end (rather than from the middle)

17
Q

in eukaryotic replication each chromosome has one/several origins of replication

A

several, forming replication bubbles that meet and are ligated together

18
Q

telomerase is ?

A

an enzyme that adds repetitive nucleotide sequences to the ends of chromosomes and therefore lengthens telomeres. This can promote evasion of both apoptosis and senescence

*linked to cancer

19
Q

Only ______1_____use DNA gyrase to supercoil their DNA

A

prokaryotes

20
Q

eukaryotes wind DNA around histones through the action of __________

A

topoisomerases

21
Q

The expected unlinked phenotype ratio from a cross between two double heterozygotes is

A

9:3:3:1, with 9/16 of the offspring double-dominant, 3/16 dominant/recessive, 3/16 recessive/dominant, and 1/16 double-recessive.

22
Q

Question 44

In a population of 18,000 Caucasians, how many are expected to be carriers of cystic fibrosis?

A. 50

B. 295

C. 590

D. 1180

A

C. 590

QUESTION EXPLANATION

C. The passage states that the frequency of the autosomal recessive condition cystic fibrosis, q2, is 1 in 3600. The frequency of the recessive allele, q, then is 1 in 60. The frequency of the dominant non-disease producing allele, p, is 59 in 60. The carriers of a population are determined by the expression 2(pq)(population) because heterozygotes are carriers and 2pq . In the given population, the number of carriers would be (2)(1/60)(59/60)(18000) or 590. Thus, choice C is correct and choices A, B, and D are eliminated.

*<strong>carrier=</strong>a person who has a recessive allele but does not express it, which is why you don’t include q2 to find the number of carriers.

23
Q

A population of sheep is in Hardy-Weinberg equilibrium. The allele for white wool (W) has an allele frequency of 0.19, and the allele for black wool (w) has an allele frequency of 0.81.

How do you find the percentage of heterozygous individuals in the population?

A

In the Hardy-Weinberg equation, heterozygotes are represented by 2pq

So the number of heterozygous individuals (Ww) is:

2pq x population = 2(0.19)(0.81)(100)= 31%

24
Q

The homozygous recessive percentage is expressed by

A

q2

from p2 + 2pq + q2

example calculation:

In corn, purple kernels are dominant to yellow. A random sample of 100 kernels is taken from a population in Hardy-Weinberg equilibrium. It is found that 9 kernels are yellow and 91 kernels are purple.

What is the frequency of the yellow allele in this population?

The homozygous recessive percentage is given as 9/100

Therefore, the frequency of the yellow allele is

q = sq. root of 9/100 = 0.3

25
Q

The recessive allele b occurs with a frequency of 0.8 in a population of crabs that is in Hardy-Weinberg equilibrium.

how do you find teh frequency of homozygous dominant individuals?

A

Allele b has a frequency q = 0.8.

p + q = 1

therefore, p = 1 - 0.8 = 0.2

Now you can determine the frequency of homozygous dominant individuals by solving for p2 : (0.2)2 = 0.04

26
Q
A
27
Q

Lighter regions of DNA have higher/lower transcription rates

A

Higher Called euchromatin (as opposed to heterochromatin)

28
Q

Telomerase have _________rich sequences

A

Guanine rich

29
Q

Intergenic regions of DNA are composed of what?

A

Non coding DNA such as tandem repeats and transposons

30
Q

T/F: are promoters included in a gene segment?

A

Yes true

31
Q

SNPs (small nucleotide polymorphism) occur most frequently where in DNA

A

Non coding, however sometimes that is not the case and an SNP can affect a phenotype

32
Q

prokaryote replication is known as

A

theta replication

33
Q

T/F: prokarytotes have only 1 chromosome and it has only 1 origin of replication

A

true

34
Q

what happens to a cell once the limit for telomere shortening has been reached

A

senescence, apoptosis, or activation of DNA repair mechanisms

35
Q

what is telomerase?

A

telomerase is an enzyme that adds repetitive nucleotide sequences to the ends of chromosomes and lengthens telomeres. This is only NORMAL in germ line, WBCs, and embryonic stem cells. It is also expressed ABNORMALLY in cancer cells.

36
Q

UV radiation causes what kind of damage to DNA backbone

A

pyrimidine dimer: when two of the same pyrimidines that reside next to eachother (T and T or C and C) on backbone form covalent bond

37
Q

What are the different types of point mutations form least to most harmful

*point mutation: replacement of one AA

A
  1. Silent: a codon is replaced with a different codon that codes for the same protein. No impact on the protein’s amino acid sequence
  2. Missense: One amino acid is replaced by another AA. Can be harmless if it occur via conservative substitution.
  3. Non-sense mutation: a stop codon replaces a regular codon and prematurely shortens the protein sequence
38
Q

T/F: all insertion and deletion mutations are frameshift mutations

A

false.

If you insert or delete a whole codon or several whole codons, you add or remove amino acids to the polypeptide without changing the reading frame.

39
Q

what is an inversion mutation

A

an insertion or deletion involving thousands of bases where a segment of chromosome is reversed end to end

40
Q

hemizygous means

A

having only one copy of a gene because the other has been cut out through mutation. may or may not be dysfunctional

aka haploid expressivity in a diploid organism

41
Q

Complementary DNA (cDNA) is DNA synthesized from a single stranded RNA (e.g., messenger RNA (mRNA) or microRNA) template in a reaction catalyzed by the enzyme reverse transcriptase. what is it commonly used for

A

cDNA is often used to clone eukaryotic genes in prokaryotes

natural instance of it is retroviruses

42
Q

Eukaryotic mRNA is monocistrionic. which means what?

A

that it contains 1 open reading frame (ORF) and obeys the “one gene one protein” rule. IE it only codes for 1 polypeptide

43
Q

Prokaryotic mRNA is __-cistrionic

A

polycistrionic

meaning it codes for more than one protein

44
Q

What are the types of non-coding eukaryotic RNA?

A
  1. Transfer RNA (tRNA) translates genetic code. It carries amino acids from the cytoplasm to the ribosome to be added to a growing protein.
  2. rRNA: ribosomal RNA.. what makes up the ribosome
  3. miRNA and siRNA: both function in post-transcriptional regulation of gene expression by binding to mRNA to either increase or decrease translation.
45
Q

In replication, what are the 3 names we can call the 3’-5’ DNA strand from which mRNA is synthesized

A

Template

non-coding

anti-sense

46
Q

splicing, capping, and addition of a poly-A tail are all __________ _________ that occur in the _______

A

post-transcriptional modifications

nucleus

47
Q

What is the function of the TATA box in eukaryotic gene regulation?

A

The TATA box is a short sequence of DNA, consisting of T and A base pairs. It helps act as a promoter sequence, telling RNA polymerase where to begin transcribing.

48
Q

What is an enhancer?

A

Enhancers are binding sites for activators, which activate genes in specific cells or body parts. They contain short sequences similar to promoter sequences and can be up or downstream of the transcription initiation sit

49
Q

eukaryotic gene expression can be regulated at what points?

A
  1. During transcription
  2. Post-translation: A protein’s activity may be regulated after translation, for example, through removal of amino acids or addition of chemical groups.
  3. During translation: Translation can be regulated through changes in the availability or activity of the “helper” proteins.

D: Post-transcription: Some transcripts can undergo post-transcriptional regulation, such as alternative splicing, which make different mRNAs and proteins from the same RNA transcript.

50
Q

T/F: In both transcription and replication, the parent strand is acting as a nucleophile

A

true

51
Q

T/F: in both replication and transcription, the polymerase requires a primer?

A

False: only DNA polymerase requires a primer. RNA polymerase acts de novo

52
Q

what do the 3 types of RNA polymerases in Eukaryotes transcribe?

A

Mnemonic: RMT I, II, III

RNA pol I: rRNA

RNA pol II: mRNA (via hnRNA intermediate)

RNA pol III: tRNA

*in prokaryotes, only one RNA pol codes for all types of RNA

53
Q

In replication, what are the 3 names we can call the 5’-3’ DNA strand that is parallel to the strand from which mRNA is synthesized?

A

non-template

sense

coding

54
Q

T/F: In prokarytotes, all types of RNA are made from the same RNA pol

A

True

55
Q

What is a haloenzyme

A

Any enzyme that is activated by a cofactor.

56
Q

prokaryotic RNA pol has a subunit “haloenzyme” that binds to ?

A

the promotor sequence

(Pribnow box at -10 or -35 sequence)

57
Q

T/F: in prokaryotes, transcription and translation can happen simultaneously, unlike in eukaryotic transcription

A

True

58
Q

hnRNA is

A

heterogeneous nuclear RNA. the primary transcript in eukaryotic transcription before post-transcriptional modification occurs.

59
Q

Alternative splicing refers to ?

A

a post-transcriptional regulated process during gene expression that results in a single gene coding for multiple proteins.

60
Q

what other modifications besides splicing must happen to hnRNA before it becomes mRNA (ie before it can be translated)

A
  1. methylation: it must have a 5’ cap made of methylated guanine (mnemonic: 5 looks like a G) *essential for translation and prevention of digestion by exonucleases in cytoplasm
  2. polyadenylation: a string of several hundred adenine nucleotides are added *essential for prevention of digestion by exonucleases in cytoplasm
61
Q

how can we explain the synthesis of 2 different polypeptides from one piece of RNA

A

differential (alternative) splicing

62
Q

the anticodon is read in ___-direction

A

3’ to 5’, where it pairs with the mRNA codon which is read in 5’-3’ direction

63
Q

the AA that tRNA carries is located on its _______end

A

3’ end

(N terminus end)

64
Q

What are the possible pairings for wobble pairing

A
65
Q

wobble pairing explains ?

A

how we don’t have 61 distinct tRNAs to match the 61 codons. ie, some tRNA can pair with more than one codon

66
Q

wobble pairing occurs at which position on codon/anticodon pairing

A

the third position (ie 3’ end of mRNA and 5’ end of tRNA)

67
Q

ribozyme

A

an RNA molecule capable of acting as an enzyme.

Best example is the ribosome that catalyzes the transfer of one AA from tRNA to polypeptide aka peptidyl transferase (specifically located in large ribosomal subunit)

68
Q

during translocation what happens

A

the ribosome shifts one place to the right, causing the uncharged tRNA to move from the P site to the E site and the tRNA with nascent protein moves from the A to the P site

69
Q

what happens next after this step?

A

peptidyle transferase catalyzes bond formation between the NH group of the incoming tRNA amino acid and the nascent polypeptide at it’s C=O group

70
Q

the key step in elongation is: peptidyle transferase in ribsosomal subunit catalyzes bond formation between the NH group of the incoming tRNA amino acid and the nascent polypeptide at its C=O group. what is the mechanism of this reaction?

A

NH group acts as nucleophile, C=O group of growing polypeptide acts as electrophile, and the newly uncharged tRNA is the leaving group

71
Q

the initiatior tRNA in prokaryotes is special because ?

A

it is the first tRNA to arrive at the ribosomal P site and is called fMet-tRNAf-met because it contains a formylmethionine, which signals translation to begin

*fMet is not found in function bacterial proteins because it undergoes post-translational processing in which this first AA is removed

72
Q

whereas the first AA in the nascent polypeptide for prokaryotes is _____, the first AA in the nascent polypeptide for Euks is _____

A

In Bacteria: fMet

In Eukaryotes and Archea: Met

73
Q

In Bacteria use a _____s ribosome

In Eukaryotes and Archea use a ___s ribosome

A

In Bacteria: 70s ribosome

In Eukaryotes and Archea: 80s ribosome

74
Q

it costs 4n phosphate bonds (aka high energy bonds) to make a peptide chain

where n=the number of amino acids.

how do you get this number?

A

Pre-initiation:

2 high energy bonds (ATP→AMP): formation of aminoacyl-tRNA

Initiation:

1 GTP (1 high energy bond): addition of small subunit to complete the ribosomal complex (ie initiation

Elongation 2 per elongation step: (n-1 elongation steps where n=#AAs)

1 GTP(1 high energy bond): addition of second aminoacyl tRNA to A site and resetting of EF-Tu

1 GTP (1 high energy bond): translocation

Termination:

1 GTP (1 high energy bond): polypeptide released/termination

________________________

Total If n=50:

(2x50)aminoacyl tRNA formation

+ (1initiation)

+(2x49=98)elongation

+(1termination)

_______________________

= 200 = 4(50)=4n

75
Q

when ATP→ADP you use ____ high energy bonds

when ATP→AMP you use ____ high energy bonds

A

when ATP→ADP you use __1__ high energy bonds

when ATP→AMP you use __2__ high energy bonds

76
Q

how many elongation steps are there in formation of a 80 AA long polypeptide?

A

n-1 (always)

so 80-1= 79 elongation steps

77
Q

does it cost any energy to perform a peptidyl transferase reaction?

(i.e. transferring the nascent polypeptide to the new charged tRNA in the A site)

A

No, it is a favorable reaction because the bond between each tRNA and its AA is a high energy bond whose hydrolysis drives the reaction.

78
Q

how does termination of translation take place?

A
  1. a stop codon appears in the A site
  2. instead of a charged tRNA, a release factor enters the A site instead
  3. this factor causes the peptidyl transferase to hydrolyze the bond between the last tRNA and the completed polypeptide (takes place in the P site)
  4. subunits dissociate
79
Q

what do prokaryotes use to start translation?

A

a ribosome binding site called Shine-Dalgarno sequence located 10 nucleotides upstream of the start codon: the sequence helps the initiation machinary on the transcript

80
Q

what is the Kozak sequence?

A

it is a 5’ UTR that is located just upstream of the start codon that is recognized by the ribosome as the translational start site

81
Q

prokaryotic vs eukaryotic ribosomes

A
82
Q
A
83
Q

What might cause a fertilized egg/embryo to implant in a place other than the uterine lining?

A

Insufficient fallopian tube cilia

84
Q

Where does most water reabsorption occur in the kidney?

A

In the loop of Henle, the active transport of NaCl from the ascending limb maintains the high salt concentration in the kidney’s medulla, facilitating the reabsorption of water from the descending limb.

More info:

The descending limb, extending from the cortex into the salty medulla, is highly permeable to water but impermeable to NaCl. Consequently, the filtrate becomes more concentrated as water is passively reabsorbed via osmosis into the medulla, where it is taken up by blood vessels.

The ascending limb, traveling from the loop’s lowest point in the medulla back toward the cortex, is impermeable to water but permeable to NaCl. NaCl is first passively reabsorbed into the medulla as the filtrate travels up the ascending limb. Yet as the limb nears the cortex, NaCl is actively transported out of the filtrate and into the medulla, maintaining the medulla’s high salt concentration while facilitating continued water reabsorption in the descending limb.

85
Q
A